Answer:
Step-by-step explanation:
I am sorry but what is the question
Answer:
Step-by-step explanation:
2 and 38/45 square yards can be sanded in 3.2 hours.
Step-by-step explanation:
1/2 of an hour is 30 minutes. so 4/9 for every 30 minutes. 1 hour is 8/9. So 3 2/10 would be 3 hours =24/9=2 6/9 and 2/10 would be ( if 5/10 is 30 minutes then 2/10 is 12 minutes.) 8/9 x 1/5 = 8/45. (24 x 5 = 120) 120/45 + 8/45 is 128/45 = 2 38/45
Answer:
5
Step-by-step explanation:
|a−b| − |c+d| , if a=−5; b=4; c=1; d=−3
= a + b - c + d
= 5 + 4 - 1 + (-3)
= 5 + 4 - 1 - 3
= 5 + 4 - 4
= <em><u>5</u></em>
Answer:
22.74 liters
Step-by-step explanation:
GIven data
Felix's washing machine uses 6 gallons of water
we are told that A gallon is approximately 3.79 liters
Hence if a gallon is approximately 3.79 liters
then 6 gallons of water will be x liters
cross multiply we have
x= 6*3.79
x= 22.74 liters
Hence 6 gallon will be 22.74 liters
Answer:
First statement is correct.
Step-by-step explanation:
If we add or subtract a constant to each term in a set: Mean will increase or decrease by the same constant. Standard Deviation will not change.
If we increase or decrease each term in a set by the same percent (multiply all terms by the constant): Mean will increase or decrease by the same percent. Standard Deviation will increase or decrease by the same percent.
For example:
Standard Deviation of a set: {1,1,4} will be the same as that of {5,5,8} as second set is obtained by adding 4 to each term of the first set.
That's because Standard Deviation shows how much variation there is from the mean. And when adding or subtracting a constant to each term we are shifting the mean of the set by this constant (mean will increase or decrease by the same constant) but the variation from the mean remains the same as all terms are also shifted by the same constant.
So according to this rule, statement (1) is sufficient to get new Standard Deviation, it'll be 30% less than the old.. As for statement (2) it's clearly insufficient as knowing mean gives us no help in getting new Standard Deviation.
