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2 years ago

1. A local fast food restaurant takes in $10,000 in a 5 hour lunch period. Write a

Mathematics

1 answer:

Leto [7]2 years ago

6 0

Answer:

8hours

Step-by-step explanation:

10000÷5=2000

so the restaurant earns 2000$ per hour

8×2000=16000

8hours=16000$

Hope that helped

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Albert borrowed $12,000 at a

Aleks04 [339]

Answer:

the answer is A

Step-by-step explanation:

8 0

2 years ago

Please solve with explanation 8 points

11111nata11111 [884]

Answer:

See below.

Step-by-step explanation:

Given :-

x² + bx + c = 0 if x₁ + x₂ = -b and x₁x₂ = c

Solving :-

a) x₁ = 1/2 and x₂ = -3/4

=> x² + -(1/2 + -3/4)x + 1/2(-3/4)

=> x² + -(-1/4)x + (-3/8)

=> x² + 1/4x - 3/8

=> 8x² + 2x - 3 = 0

b) x₁ = 1 + √5 and x₂ = 1 - √5

=> x² + -(1 + √5 + 1 - √5)x + (1 + √5)(1 - √5)

=> x² - 2x + 1 - 5

=> x² - 2x - 4 = 0

3 0

1 year ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

2 years ago

Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)

icang [17]

The equation is $y = \frac{3}{2} x - \frac{11}{2}$

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$

So, the midpoint will be $(\frac{-1+7}{2} , \frac{1-5}{2} )\\\\$

= $(3,-2)$

It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula $\frac{y_2-y_1}{x_2-x_1}$

The slope is $\frac{-5-1}{7+1}$ = $-\frac{2}{3}$

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of $-\frac{2}{3}$ is $\frac{3}{2}$

To write an equation, substitute the values in y = mx + c

WHere,

y = -1

x = 3

m = 3/2

Solving for c:

$-1 = \frac{3}{2} X 3 + c\\\\-1 = \frac{9}{2}+c\\ \\c = \frac{-2-9}{2} \\\\c = \frac{-11}{2}$

Thus, the equation becomes:

$y = \frac{3}{2} x - \frac{11}{2}$

7 0

2 years ago

A right triangle has an area of 38 square units

oksian1 [2.3K]

Answer:

1 | 38

2 | 76

3 | 114

5 | 190

1/2 | 19

2/3 | 25.33

Step-by-step explanation:

I am assuming that you need to multiply the area by the scale factors

6 0

2 years ago