ANYONE PLEASE HELP!!!

Mathematics

2 answers:

Nana76 [90]2 years ago

5 0

457 irk sorry I don’t do this

Alona [7]2 years ago

4 0

Closed circle on -18 shaded to the left because it’s less than or equal to -18 (i think u meant to put -18 not -108)

You might be interested in

P and q are points on the line 2y-5x=10

schepotkina [342]

Answer:

$2y-5x =10\\when \ x = 0, \ 2y = 10 => y = 5\\\\\\when \ y = 0, -5x =10 => x =-2\\\\Therefore \ the \ coordinates \ of \ the \ points \ p \ and \ q\ are \ (0, 2) \ and \ (-2, 0)$

7 0

2 years ago

Help pleaseeee due at 4:00

Archy [21]

Answer:

the total cost would be $15,900

Step-by-step explanation:

<em>hope this helped & good luck <33</em>

5 0

2 years ago

Can someone answer these questions ? thank you

Naya [18.7K]

Answer:

Step-by-step explanation:

12a)To rationalize the denominator, multiply the denominator and numerator by √5.

$\frac{15}{\sqrt{5}}=\frac{15*\sqrt{5}}{\sqrt{5}*\sqrt{5}}\\\\=\frac{15\sqrt{5}}{5}\\\\=3\sqrt{5}$

b) (a+b)² = a² + 2ab + b²

(1 +√3)² = 1² + 2*1*√3 + (√3)²

= 1 + 2√3 + 3

= 4 + 2√3

a = 4 ; b =2

13) (a + b)(a - b) = a² - b²

$\frac{(6-\sqrt{5})(6+\sqrt{5})}{\sqrt{31}}=\frac{6^{2}-(\sqrt{5})^{2}}{\sqrt{31}}\\\\ =\frac{36-5}{\sqrt{31}}\\\\=\frac{31}{\sqrt{31}}\\\\=\frac{31*\sqrt{31}}{\sqrt{31}*\sqrt{31}}\\\\=\frac{31\sqrt{31}}{31}\\\\=\sqrt{31}$