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2 years ago

HELP ME (How many cubes with side length 1/2 cm does it take to fill the prism

Mathematics

1 answer:

Natalija [7]2 years ago

8 0

answer:

step-by-step explanation:

for this you would find the volume and then divide by 1/2

v = l x w x h

v = (1)(2)(3/2)

v = 3

now, divide

3 ÷ 1/2 = 6

therefore, it will take 6 half cubes to fill up the container

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2 years ago

What is vaule of f^-1 (-4)

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Answer:

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Step-by-step explanation:

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2 years ago

Y=1/2×-6 ×=-4 what is the solution to the system of equations

hodyreva [135]

Answer:

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Step-by-step explanation:

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2 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

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2 years ago