Answer: please find attached to see the structure.
1. THE STRUCTURE OF BENZOIC ACID AND FLUORENE, soluble in ether and insoluble in water.
2. THE STRUCTURE OF CARBOXYLIC ACID BEEN EXTRACTED.
Explanation: the mixture of benzoic acid and fluorene are the first diagrams which shows the carboxylic acid attached to the benzene ring, which are soluble in ether and insoluble in water. When dissolved in NaOH(aq) is the carboxy ion becomes soluble in water but insoluble in ether, this is seen in the second diagram.
The third diagram shows the carboxylic acid been precipitated and soluble in ether but insoluble in water.
NOTE THE TWO MAIN DIAGRAM IS THE FIRST AND THE LAST DIAGRAM, WHERE CARBOXYLIC ACID DISSOLVES IN AQUEOUS SODIUM HYDROXIDE, AND WHEN THE ACID IS BEEN PRECIPITATED IN AQUEOUS HCl.
ALSO NOTE THE CHANGE IN BENZOIC RING MIXED WITH FLUORENE TO THAT OF THE ACID BEEN EXTRACTED.
Hope together with the picture, this has helped you.
Aluminum sulfide : Al₂S₃
ratio cation : anion = 2 : 3
<h3>Further explanation</h3>
Given
Compound of Aluminium
Required
cations anions ratio
Solution
Salt can be formed from cations and anions which have their respective charges.
In the chemical compound formula these charges are crossed with each other
For aluminum it has a +3 charge
1. Aluminum carbide : Al₄C₃
ratio cation : anion = 4 : 3
2. Aluminum chloride : AlCl₃
ratio cation : anion = 1 : 3
3. Aluminum sulfide : Al₂S₃
ratio cation : anion = 2 : 3
4. Aluminum nitride : AlN
ratio cation : anion = 1 : 1
Answer:
0.077M is the concentration of the hydroxyl ion
Explanation:
Dilution factor is the ratio between the aliquot that is taken of a solution and the total volume of the diluted solution.
For the problem, dilution factor is:
7.53cm³ / 147cm³ =<em> 0.05122</em>
To obtain molarity of a diluted solution you must multiply dilution factor and initial molarity of the solution, thus:
1.5 M × 0.05122 = <em>0.077M is the concentration of the hydroxyl ion</em>
Answer:
CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)
Explanation:
We have the reactants as calcium chloride and potassium carbonate. Recall that we are expecting that the reaction will yield a precipitate. We must keep that in mind as we seek to write its balanced chemical reaction equation.
So we now have;
CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)
Recall that the rule of balancing chemical reaction equation states that the number of atoms of each element on the right side of the reaction equation must be the same as the number of atoms of the same element on the left hand side of the reaction equation.
Answer:
HCl conc.= 6.0mol/L
Explanation:
From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,
