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Lady bird [3.3K]

2 years ago

11

Jackie won tickets playing the bowling game at the local arcade. The first time, she won 60 tickets. The second time, she won a

bonus, which was 4 times the number of tickets of the second prize. Altogether she won 200 tickets. How many tickets was the second prize?

1 answer:

Fynjy0 [20]2 years ago

4 0

Answer: i'm pretty sure she got 35 the second time. hope this helps

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Robert needs to cut four shelves from a board that is 2.5 meters long. The second shelf is 18 cm longer than twice the length of

g100num [7]

STEP 1:
convert meters to centimeters
100 cm= 1 meter

= 100 cm/m * 2.5 m
= 250 cm

STEP 2:
x= length of first shelf
2x+18= length of second shelf
x-12= length of third shelf
x+4= length of fourth shelf

since the whole board has to be used, add lengths of all shelves and set it equal to the whole length of the board (250 cm).

x + (2x+18) + (x-12) + (x+4)= 250 cm
combine like terms
5x + 10= 250
subtract both sides by 10
5x= 240
divide both sides by 5
x= 48

STEP 3:
find length of second shelf
= 2x + 18
= 2(48) + 18
= 114 cm

CHECK:
x + (2x+18) + (x-12) + (x+4)= 250
48 + (2(48)+18) + (48-12) + (48+4)= 250
48 + (96+18) + 36 + 52= 250
48 + 114 + 36 + 52= 250
250= 250

ANSWER: Shelf two is 114 cm.

Hope this helps! :)

8 0

2 years ago

The sum of 3 times a number and 7

leva [86]

Algebraically, that will be expressed as:

$3n +7$

7 0

2 years ago

4x + 5 – 2x = 15. Solve for c

Vinil7 [7]

Answer: x=5

Step-by-step explanation:

7 0

2 years ago

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The length of a rectangle is increasing at a rate of 9 cm/s and its width is increasing at a rate of 7 cm/s. When the length is

Hunter-Best [27]

Answer:

<em>129 </em> $cm^2/s$

Step-by-step explanation:

Increasing rate of length, $\frac{dl}{dt}$ = 9 cm/s

Increasing rate of width, $\frac{dw}{dt}$ = 7 cm/s

Length, l = 12 cm

Width, w = 5 cm

To find:

Rate of increase of area of rectangle at above given points.

Solution:

Formula for area of a rectangle is given as:

$Area = Length \times Width$

OR

$A = l \times w$

Differentiating w.r.to t:

$\dfrac{d}{dt}A = \dfrac{d}{dt}(l \times w)\\\Rightarrow \dfrac{d}{dt}A = w \times \dfrac{d}{dt}l +l \times \dfrac{d}{dt}w$

Putting the values:

$\Rightarrow \dfrac{dA}{dt} = 5 \times 9 + 12 \times 7\\\Rightarrow \dfrac{dA}{dt} = 45 + 84\\\Rightarrow \bold{\dfrac{dA}{dt} = 129\ cm^2/sec}$

5 0

2 years ago

Given: segment AB || segment DE, C is the midpoint of segment DB. Prove: ΔACB ≅ ΔECD Fill in the missing reason for the proof. A

OleMash [197]

Answer:

Given: Segment AB || segment DE, C is the midpoint of segment DB.

Prove: ΔA CB ≅ ΔE CD

Proof: In ΔA CB and ΔE CD

C is the Mid point of B D.

BC=C D→ definition of midpoint

∠A CB= ∠ EC D→→vertical angles are congruent

∠BAC=∠DEC→→[AB║DE,so alternate angles are equal]

→→ΔA CB ≅ ΔE CD[A AS or A SA]

Option B: vertical angles are congruent

4 0

2 years ago

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