All categories

2 years ago

Find the greatest common factor of 4c3 and 6m2.

Mathematics

1 answer:

Brums [2.3K]2 years ago

3 0

Answer:

The GCF is 2

Step-by-step explanation:

Here, we want to find the greatest common factors of the two terms

We have the terms written in terms of the products of their multiples as follows;

4c^3 = 2 * 2 * c * c* c

6m^2 = 2 * 3 * m * m

As we can see, the greatest common factor of the two is simple the value 2

You might be interested in

What is the measure of

Andreas93 [3]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Katie is making posters for the school play. She borrows a 12-pint set of paint from the art teacher. To make her posters really

xenn [34]

12 divided by 4 is 3 so 3 pints of paint

3 0

2 years ago

Read 2 more answers

What is the standard deviation for 9, 8, 1, 11, 1, 12, 9, 12, 4, 12

shtirl [24]

Answer

I can't tell what you're asking but here is all the things

Step-by-step explanation:

Total Numbers: 10

Mean (Average): 7.9

SD: 4.38305

Variance (SD): 19.21111

Population SD: 4.15812

Variance(Population SD): 17.29

6 0

2 years ago

The probability of an event happening is 23%. What is the complement of the event?

solong [7]

Answer:The probability of the complement of an event is one minus the probability of the event. Since the sum of probabilities of all possible events equals 1, the probability that event A will not occur is equal to 1 minus the probability that event A will occur.

Step-by-step explanation:Complement of an Event: All outcomes that are NOT the event. So the Complement of an event is all the other outcomes (not the ones we want). And together the Event and its Complement make all possible outcomes.

7 0

2 years ago

A certain restaurant always overbooks. If possible. At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53

oee [108]

Answer:

The probability that the restaurant can accommodate all the customers who do show up is 0.3564.

Step-by-step explanation:

The information provided are:

At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
If the probability of a party not showing up is 0.04.
Assuming independence.

Let X denote the number of parties that showed up.

The random variable X follows a Binomial distribution with parameters n = 53 and p = 0.96.

As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.

Compute the probability that the restaurant can accommodate all the customers who do show up as follows:

$P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564$

Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.

7 0

2 years ago