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2 years ago

Prove: a/(b+c)+b/(a+c)+c/(a+b)<2

Mathematics

1 answer:

faust18 [17]2 years ago

4 0

Answer:

Step-by-step explanation:

a/(b+c) < 2a/(a+b+c)

b/(a+c) < 2b/(a+b+c)

c/(a+b) <2c/ (a+b+c)

so a/(b+c)+b/(a+c)+c/(a+b) <2(a+b+c)/(a+b+c)=2

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The table shows the results of a poll of 200 randomly selected juniors and seniors who were asked if they attended prom. Find th

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Answer:

(a) $\frac{7}{25}$

(b) $\frac{19}{116}$

Step-by-step explanation:

Number of juniors who attended prom,n(J)=28

Number of seniors who attended prom,n(S)=97

Total of those who attended prom=125

Number of juniors who did not attend prom,n(J')=56

Number of seniors who did not attend prom,n(S')=19

Total of those who attended prom=75
Total Number of students=200

(a) P (a junior who did not attend prom)

$P(J')=\frac{56}{200}= \frac{7}{25}$

(b)

$P(Senior)=\frac{116}{200}$

$P ($did not attend prom$ | senior)=\frac{\text{P(seniors who did not attend prom)}}{P(Senior)} \\=\frac{19/200}{116/200} \\=\frac{19}{116}$

(c)P (junior | attended prom)

$P(Senior)=\frac{84}{200}$

$P (Junior|$ attended prom$)=\frac{\text{P(juniors who attended prom)}}{P(\text{those who attended prom)}} \\=\frac{28/200}{125/200} \\=\frac{28}{125}$

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0.10d + 0.25q = 3.55
q = d + 3

0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes

q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters

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2 years ago