Answer:
Step-1 : Reflect the original figure around the x-axis.
Step-2 : Slide the new figure 7 units to the right.
Answer:
Step-by-step explanation:
Given
per mile
Solving (a): Linear Equation
The total charges (c(x)) is: the base charge + the rate * number of miles (x).
So, we have:
Solving (b): Cost of rent, if miles = 160
This implies that x = 160
So, we have:
Answer:
Both equation represent functions
Step-by-step explanation:
The function is the relation that for each input, there is only one output.
A. Consider the equation
This equation represents the function, because for each input value x, there is exactly one output value y.
To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.
When you intersect the graph of the function with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.
B. Consider the equation
This equation represents the function, because for each input value x, there is exactly one output value y.
When you intersect the graph of the function with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.
Answer: B
Number on the left: x-value
Number on the right: y-value
If there are 2 y-values for one x-value it is NOT considered a function.
For instance in the answer:
(2,3), (2,4), (3,3), (3,4)
You can clearly see that the x-values (2 & 3) repeat more than once; therefore, it is NOT a function.
On the other hand if you have 2 DIFFERENT x-values for the same y-value it IS A FUNCTION.
For ex D: (2,4), (3,4), (5,4), (6,4)
As you can see there are 4 DIFFERENT x-values with same y-value; therefore it is A FUNCTION
To make it easier:
If x-values appear more than once = NOT A FUNCTION
If x-values appear only ONCE = FUNCTION
Remember: y-values are ALLOWED to repeat
I hope this helps. If you have any questions please let me know in the comments.