Answer:
-When (2×-5) intersects at ×-axis the value of × will be zero.
=>F(×)=× 0=2×-5
hence,
0,=2×-5
5=2×
=>×=5/2
Step-by-step explanation:
hpe it hlps
We have:
Event A ⇒ P(A) = 0.16
Event B ⇒ P(B) = 0.09
Probability of event B given event A happening, P(B|A) = P(A∩B) / P(A) = 0.12
By the conditional probability, the probability of event A and event B happens together is given by:
P(B|A) = P(A∩B) ÷ P(A)
P(B|A) = P(A∩B) ÷ 0.16
0.12 = P(A∩B) ÷ 0.16
P(A∩B) = 0.12 × 0.16
P(A∩B) = 0.0192
When two events are independent, P(A) × P(B) = P(A∩B) so if P(A∩B) = 0.0192, then P(B) will be 0.0192 ÷ 0.16 = 0.12 (which take us back to P(B|A))
Since P(B|A) does not equal to P(B), event A and event B are not independent.
Answer: <span>Events A and B are not independent because P(B|A) ≠ P(B)</span>
Isolate the z. Note the equal sign. Subtract 1/7z to both sides
1/7z (-1/7z) + 2 = -6/7z (-1/7z)
2 = -6/7z - 1/7z
Simplify. Combine like terms
2 = -7/7z
2 = -1z
Isolate the z. Divide -1 from both sides
(2)/-1 = (-1z)/-1
z = 2/-1
z = -2
-2 is your answer
hope this helps