So,
Let x represent Joe's weight and y represent Jeff's weight.
"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250
We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250
Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250
We will use Elimination by Substitution.
2y - 20 + y + 10 = 250
Collect Like Terms.
3y - 10 = 250
Add 10 to both sides.
3y = 260
Divide both sides by 3.
Substitute again.
Multiply.
Subtract.
Check.
"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.
"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.
The Square Root Of 8100 Is 90. That Will Be The Only Square Root Because The Square Root Of 90 Is A Decimal So You Would Stop There.
1,15 3,5 are the only factor pairs
Answer:
Required largest volume is 0.407114 unit.
Step-by-step explanation:
Given surface area of a right circular cone of radious r and height h is,
and volume,
To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,
subject to,
We know for maximum volume . So let be the Lagranges multipliers be such that,
And,
Substitute (3) in (2) we get,
Substitute this value in (1) we get,
Then,
Hence largest volume,
Assuming you are solving for x...