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2 years ago

Can anyone help me with this ?

Mathematics

1 answer:

attashe74 [19]2 years ago

5 0

12ujajajwjdjejwejwiqkjs

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Consider this quadratic equation. 2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?

Mariulka [41]

Answer:

$\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)}$

Step-by-step explanation:

Quadratic formula: $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

$2x^2-1=3x+4\\\\2x^2-3x-5=0\\\\\\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)} \\\frac{3+-\sqrt{9+40} }{4}$

$x = \frac{3+-7}{4}$

Hope this helps and God bless!

6 0

1 year ago

Solve each equation.Show your work. Can someone help me please??

Inga [223]

Answer:

1/2a = -5

a = (-5 x 2) : 1

a = -10

8 - b = 9,5

b = 8 - 9,5

b = -1,25

0,1 = -10c

c = 0,1 : -10

c = -0,01

I hope it's helpful.

3 0

2 years ago

For what value of c does x^2−2x−c=4 have exactly one real solution? PLEASE HELP!!!!!!!

Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

$x^2-2x-(c+4)=0$ .

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic $ax^2+bx+d$ , the discriminant is $\sqrt{b^2-4ad}$ .

(The discriminant is more commonly known as $\sqrt{b^2-4ac}$ , but I changed the variable since we already have a $c$ in the quadratic given.)

In the quadratic above, we have $a=1$ , $b=-2$ , and $d=-(c+4)$ . Plugging this into the formula for the discriminant, we have

$\sqrt{(-2)^2-4(1)(-(c+4))$ .

Using the distributive property to expand and simplifying, the expression becomes

$\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.$

Setting the discriminant equal to 0 gives

$2\sqrt{c+5}=0$ .

We can then solve the equation as usual: first, divide by 2 on both sides:

$\sqrt{c+5}=0$ .

Squaring both sides gives

$c+5=0$ ,

and subtracting 5 from both sides, we have

$\boxed{c=-5}.$

3 0

1 year ago

Select the correct answer from each drop-down menu. Javier purchased a digital camera for $384. The value of the camera deprecia

Eva8 [605]

Answer:

it will take 3 yrs for the value of camera to reach $162.

Step-by-step explanation:

Pd = P(1-R/100)^T

162 = 384(1-25/100)^T

162/384 = (3/4)^T

27/64 = (3/4)^T

(3/4)^3 = (3/4)^T

T = 3

3 0

2 years ago

Given that a rectangle has a length of 5/2x + 10 with a width of 5/2x + 5, formulate an expression to represents the area of the

stepan [7]

Answer:

Step-by-step explanation:

L = ⁵/₂x + 10

W = ⁵/₂x + 5

A = L•W

A = (⁵/₂x + 10)(⁵/₂x + 5)

A = ⁵/₂x•⁵/₂x + ⁵/₂x•5 + 10•⁵/₂x + 10•5

A = ²⁵/₄x² + ²⁵/₂x + ⁵⁰/₂x + 50

A = ²⁵/₄x² + ⁷⁵/₂x + 50

Or if yoy mean:

L = 5/(2x) + 10

W = 5/(2x) + 5

A = [5/(2x) + 10][5/(2x) + 5] = 25/(4x²) + 75/(2x) + 50

8 0

2 years ago