Answer:
18 s
Step-by-step explanation:
We are given that
Distance between Bob and John=450 feet
Speed of Bob=11ft/s
Speed of John=14 ft/s
We have to find the time after they will meet when they are travel towards to each other.
Total distance traveled by Bob and John in 1 s=11+14=25 ft
25ft covered by Bob and John in 1 s
1 ft covered by Bob and John in
450 ft covered by Bob and John in
Hence, they will meet after 18 s.
Step-by-step explanation:
soo here is the answer
170 degree is the value of =x
and the value of uly is 110 degree
Answer:
B) -125a^11
Step-by-step explanation:
(-5a^2)^3·a^5 = (-5)^3·a^6·a^5
= (-5)^3·a^(2·3)·a^5
= (-5)^3·a^6·a^5
= -125·a^(6+5)
= -125·a^11 . . . . matches choice B
_____
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
Answer:
F(d) = 30 + 0.50d
Step-by-step explanation:
Given
Charges = P8.00 ---- first 4 km
Additional = P0.50
Required
Write a function to address the scenario.
Represent the whole distance covered with d.
First,we need to determine the total charges for the first four hours.
Charges = 8.00 * 4
Charges = 32.00
Next, we determine the charges for additional distance.
Charges = 0.50 * (d - 4)
d - 4 is the remaining distance after the first 4.
Charges = 0.50d - 2
The function is then written as;
F(d) = 32 + 0.50d - 2
F(d) = 32 - 2 + 0.50d
F(d) = 30 + 0.50d