5:7 (pencils to pens)
7/12 chance that a pen from the first box will be selected.
4:4 (colour pencils to crayons)
4/8 = 1/2 chance that a crayon from the second box will be selected.
The probability of picking both:
7/12 * 1/2 = 8/24 = 1/3
Answer: (3x + 4y)(3x + 4y)
Step-by-step explanation: So you are supposed to "unfoil". So you would find two numbers multiplied together to make 9x^2 which would be 3x. Then you would find two numbers that can be multiplied together to get 16y^2 which would be 4y. To check your work, you do 3x times 3x. Then 4y times 4y. Then 4y times 3x plus 3x times 4y. You get 9x^2 + 24xy plus 16y^2.
-6a-5=-95 Given
-6(15)-5=-95 Substitution
a=15 idk the reason im not real good at this but i tried!
Hope you have a nice day
Answer:
g(x) = - (x² + 3x + 2) = - x² - 3x - 2
Step-by-step explanation:
The graph represents the function f(x) = x² + 3x + 2.
Now, g(x) is the function which is obtained by reflecting f(x) across the x-axis.
While a graph of a function reflects across x-axis then its y-values will change sign for a fixed value of x.
Therefore, the function g(x) will be given by
g(x) = - (x² + 3x + 2) = - x² - 3x - 2 (Answer)
Answer:
- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that
P(8 arrive) = (0.56)^8 = 0.00967
- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.
Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be
(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).
So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079
- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,
P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)
= 1 - P(overbooked) - P(exactly booked)
= 1 - 0.00967 - 0.06079
= 0.9295.
Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.
Hope that helps!
Have a great day :P