Answer:
<h2>A. a spring & B. a well dried into an aquifer.</h2>
Answer:
final displacement lf = 0.39 m
Explanation:
from change in momentum equation:
![\delta p = m \sqrt(2g * y/x)* [\sqrt li + \sqrt lf]](https://tex.z-dn.net/?f=%5Cdelta%20p%20%3D%20m%20%5Csqrt%282g%20%2A%20y%2Fx%29%2A%20%5B%5Csqrt%20li%20%2B%20%5Csqrt%20lf%5D)
given: m = 0.4kg, y/x = 19/85, li = 1.9 m,
\delta p = 1.27 kg*m/s.
putting all value to get the final displacement value
![1.27 = 0.4\sqrt(2*9.81 *(19/85))* [\sqrt 1.9 + \sqrt lf]](https://tex.z-dn.net/?f=1.27%20%3D%200.4%5Csqrt%282%2A9.81%20%2A%2819%2F85%29%29%2A%20%5B%5Csqrt%201.9%20%2B%20%5Csqrt%20lf%5D)
final displacement lf = 0.39 m
Answer:
letter B
none zero digit are significant figures
Answer:
3 seconds
Explanation:
Since h(t) represents the height and t represents the time, we can set the equation equal to 150 to find t.
-16t^2+96t+6=150
Subtract 150 from both sides to set the equation equal to 0, to find the solutions.
-16t^2+96t-144=0
Factor out -16, because all of the terms are divisible by it.
-16(t^2+6t+9)=0
Now we can focus on the terms inside the parenthesis and factor it again.
t^2-6t+9=0
We need to find two value that can be multiplied to get 9 and added to get -6.
-3 and -3 works.
Thus, we get (x-3)(x-3).
Now solve for 0.
x-3=0
x=3
The object reaches its maximum height after 3 seconds.
The force that peter applies to the object of distance 40m is 75N.
<h3>HOW TO CALCULATE FORCE</h3>
The force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;
Force = Work done ÷ distance
According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:
Force = 3000J ÷ 40m
Force = 75N
Therefore, the force that peter applies to the object of distance 40m is 75N.
Learn more about force at: brainly.com/question/26115859
