Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
Answer:
(9a4 + 2a2 + 5) – (16a4 – 7a2 + 1)
A. 25a4 – 5a2 – 4
B. –7a4 – 5a2 + 6
C. 25a8 + 9a4 + 6
D. –7a4 + 9a2 + 4
5.Multiply 9x2(2x2 + 8x).
A. 18x4 + 72x3
B. 18x2 + 72x3
C. 11x4 – 17x3
D. 90x4
Answer:
See below.
Step-by-step explanation:
The set of all positive integers N is countable so we need to show that there is a 1 to 1 correspondence between the elements in N with the set of all odd positive integers. This is the case as shown below:
1 2 3 4 5 6 ...
| | | | | | ....
1 3 5 7 9 11....
Answer:
B. m+4
Step-by-step explanation:
You are just writing the same equation but backwards so that the numbers still stay the same as well as the answer.
Step-by-step explanation:
12x31
do that and you get the answer
