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Answer:
The equation of the line we want to write is 4y = -x + 22
Step-by-step explanation:
Here, we want to write the equation of a line
.
The standard equation of a straight line is given as:
y = mx + c
where m is the slope and c represents the y-intercept
Now, let’s look at the line y = 4x + 16
The slope of this line is 4
Now, the equation of the line we want to write is perpendicular to this line
When two lines are perpendicular, the product of their slopes = -1
Hence;
m * 4 = -1
m = -1/4
So the slope of the line we want to write is -1/4
Now, using the point-slope form for the new equation;
y-y1/x-x1 = m
From the point given (x1,y1) = (10,3)
Thus;
y-3/x-10 = -1/4
4(y-3) = -1(x - 10)
4y - 12 = -x + 10
4y = - x + 10 + 12
4y = -x + 22
Answer:
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Step-by-step explanation:
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I would say that there are 29 boys in the class.
Solve for x first
-6x - 42 = -4x -2
-6x = -4x + 40
- 2x = 40
X = -20
The equation has one solution
