(1/A) dA/dt= C where A is the population of ants and C is a constant
ln(A) = C*t + C1 where C1 is another constant that comes out of integration and t is time in days.
Plugging in: at t=0, A= 100 so C1 = ln(100) = 4.605
at t=3, A=230 so ln(230) = 3*C +4.605 so C = 0.278
Final equation:
ln(A) = 0.278t + 4.605
or:
A = exp(0.278t + 4.605)
After 14 days, A = exp(0.278*14 + 4.605) = 4875.2
Answer:
idk if this is right or not, but I got africa...
The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula , equivalent to the <em>recurrence</em> formula .
<h3>What is the missing element in a sequence?</h3>
A sequence is a set of elements which observes at least a <em>defined</em> rule. In this question we see a sequence which follows this rule:
(1)
Now we prove that given expression contains the pattern:
n = 0
7
n = 1
7 + (- 1)² · 2² = 7 + 4 = 11
n = 2
7 + (- 1)² · 2² + (- 1)³ · 3² = 11 - 9 = 2
n = 3
7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² = 2 + 16 = 18
n = 4
7 + (- 1)² · 2² + (- 1)³ · 3² + (- 1)⁴ · 4² + (- 1)⁵ · 5² = 18 - 25 = - 7
The <em>missing</em> pattern behind the sequence 7, 11, 2, 18, -7 is described by the formula , equivalent to the <em>recurrence</em> formula .
To learn more on patterns: brainly.com/question/23136125
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Answer:
1655
Step-by-step explanation:
Note the common difference d between consecutive terms of the sequence
d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3
This indicates the sequence is arithmetic with sum to n terms
= [ 2a₁ + (n - 1)d ]
Here a₁ = - 4, d = 3 and n = 90, thus
= [ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655
This is probably way overcomplicated but i cant remember how to do it
w = n
l = 2n+1
w*l = 66
n(2n+1) = 66
2n^2 + n =66
2n^2 + n - 66 = 0
using quadratic equation
n = 11/2
width = 11/2 = 5.5
length = 11 + 1 = 12