Was there a chart with this?
W equals 7 :) you’re welcome
Answer:
Imperfect substitutes
explanation:
The choices above are not perfect substitutes, meaning they can not be perfectly or directly replace the other. Imperfect substitutes are close substitutes but not perfect substitutes. Unlike perfect substitutes, imperfect substitutes satisfies same utility but has different characteristics and therefore not entirely substitutable. For example, while one may want to have the 40 marks too, he'd rather have 60 marks even if the criteria for a 60 mark score was increasingly hard.
Answer:
<h3>Rules for division with a mixed number and a whole number
</h3>
<h3>The mixed number is converted into an improper fraction and the whole number is written as a fraction with denominator 1.
</h3>
<h3> 2.Division of the fractions is converted into a multiplication operation by multiplying the improper fraction with the reciprocal of the whole number.
</h3>
<h3> 3.The resulting fraction, if required, is written as a mixed number in simplest form.</h3>
<h2>I WILL GIVE YOU EXAMPLES AND LET ME JUST HOPE YOU GET IT ;)</h2><h2 /><h3>Example1: </h3><h3>Divide. Write your answer as a mixed number in simplest form.
</h3><h3>
</h3><h3>213÷7
</h3><h3>Solution
</h3><h3>Step 1:
</h3><h3>
</h3><h3>First, we write the mixed number 213 as an improper fraction
</h3><h3>
</h3><h3>213=(2×3+1)3=73; 7=71
</h3><h3>
</h3><h3>Step 2:
</h3><h3>
</h3><h3>The division is converted into multiplication as follows
</h3><h3>
</h3><h3>213÷7=73÷71=73×17
</h3><h3>Step 3:
</h3><h3>
</h3><h3>Multiplying numerators and denominators
</h3><h3>
</h3><h3>73×17=(7×1)(3×7)=721
</h3><h3>Step 4:
</h3><h3>
</h3><h3>721 can be simplified and written as follows
</h3><h3>
</h3><h3>721=13
</h3><h3>Step 5:
</h3><h3>
</h3><h3>So, 213÷7=13</h3><h3 /><h3>example2: </h3><h3 /><h3>Divide. Write your answer as a mixed number in simplest form.
</h3><h3>
</h3><h3>5÷134
</h3><h3>Solution
</h3><h3>Step 1:
</h3><h3>
</h3><h3>First, we write the mixed number 134 as an improper fraction
</h3><h3>
</h3><h3>134=(1×4+3)4=74; 5=51
</h3><h3>
</h3><h3>Step 2:
</h3><h3>
</h3><h3>5÷134=51÷74=51×47
</h3><h3>Step 3:
</h3><h3>
</h3><h3>Multiplying numerators and denominators
</h3><h3>
</h3><h3>51×47=(5×4)(1×7)=207
</h3><h3>Step 4:
</h3><h3>
</h3><h3>207 can be written as a mixed number as follows
</h3><h3>
</h3><h3>207=267
</h3><h3>Step 5:
</h3><h3>
</h3><h3>So, 5÷134=267</h3><h3 /><h3>OK HOPE THIS HELPS YOU :')</h3><h3 /><h3>PLEASE MARK ME BRILLIANT :3 </h3><h3>THANK YOU -</h3>
I think this is what you want? When multiplying with exponents, you either add or multiply the exponents.
When you multiply the exponent:
(x²)³ =
= 9
When you add the exponents:
(x²)(x³) =
(x²)(x²) =