At 25 °C with 10 g/kg of water vapor in the air, precipitation is likely or not likely.

1

Otrada [13]

Answer:

A. the iron atoms are gaining kinetic energy

Explanation:

when the iron melted and solidifies it loses potential energy and changes to kinetic energy

3 0

1 year ago

How many valence electrons are represented in the following electron configuration? 1s22s22p5

Alex

Answer is: d) 7.
Electron configuration: 1s²2s²2p⁵.
Valence electrons are in 2s and 2p orbitals.
Valence electrons are outer shell electrons (transition metal can have a valence electrons in an inner shell) that is associated with an atom and they can form chemical bond. Valence eletrons determine chemical proporties of element.

7 0

2 years ago

Choose the word that correctly completes the analogy.

irakobra [83]

Answer:

Minera and Aragonite

Explanation:

Limestone is a common type of carbonate sedimentary rock. It is composed mostly of the minerals calcite and aragonite, which are different crystal forms of calcium carbonate (CaCO 3). Limestone forms when these minerals precipitate out of water containing dissolved calcium.

8 0

1 year ago

What statement best explains how life functions a unicellular organism are carried out?

lbvjy [14]

Answer:

C). The structures in the cell work together to perform its life functions.

Explanation:

Unicellular organisms are characterized as organisms that are able to perform all the life functions through a single-cell. The third statement correctly elaborates how 'single-celled organisms carry out these life functions by cooperatively employing the structures lying inside the cell.' The first option is incorrect as it talks about multi-cells which doesn't even exist in unicellular organisms. While the second option is wrong because there are no tissues formed of single-cell. The last option is incorrect as the specialized cells perform different life functions in multi-cellular organisms. Thus, option C is the correct answer.

8 0

2 years ago

Air is compressed from an inlet condition of 100 kPa, 300 K to an exit pressure of 1000 kPa by an internally reversible compress

ElenaW [278]

Answer:

(a) $W_{isoentropic}=8.125\frac{kJ}{mol}$

(b) $W_{polytropic}=7.579\frac{kJ}{mol}$

(c) $W_{isothermal}=5.743\frac{kJ}{mol}$

Explanation:

Hello,

(a) In this case, since entropy remains unchanged, the constant $k$ should be computed for air as an ideal gas by:

$\frac{R}{Cp_{air}}=1-\frac{1}{k} \\\\\frac{8.314}{29.11} =1-\frac{1}{k}\\$

$0.2856=1-\frac{1}{k}\\\\k=1.4$

Next, we compute the final temperature:

$T_2=T_1(\frac{p_2}{p_1} )^{1-1/k}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.4}=579.21K$

Thus, the work is computed by:

$W_{isoentropic}=\frac{kR(T_2-T_1)}{k-1} =\frac{1.4*8.314\frac{J}{mol*K}(579.21K-300K)}{1.4-1}\\\\W_{isoentropic}=8.125\frac{kJ}{mol}$

(b) In this case, since $n$ is given, we compute the final temperature as well:

$T_2=T_1(\frac{p_2}{p_1} )^{1-1/n}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.3}=510.38K$

And the isentropic work:

$W_{polytropic}=\frac{nR(T_2-T_1)}{n-1} =\frac{1.3*8.314\frac{J}{mol*K}(510.38-300K)}{1.3-1}\\\\W_{polytropic}=7.579\frac{kJ}{mol}$

(c) Finally, for isothermal, final temperature is not required as it could be computed as:

$W_{isothermal}=RTln(\frac{p_2}{p_1} )=8.314\frac{J}{mol*K}*300K*ln(\frac{1000kPa}{100kPa} ) \\\\W_{isothermal}=5.743\frac{kJ}{mol}$

Regards.

8 0

2 years ago