Answer:
0.9307 moles have been introduced into the bag.
Explanation:
Pressure of the gas within the bag,P = 1.00 atm
Temperature of the gas remains at room temperature,T=20.0 °C = 293.15 K
Volume of the gas in the bag = V = 22.4 L
Number of moles of gas = n
Using an ideal gas equation:
n = 0.9307 moles
0.9307 moles have been introduced into the bag.
We all know, Density = Mass/ volume.
When volume increases and the mass remains the same , the density will decrease considerably.
<h3>
Answer:</h3>
132.03 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- The equation for the reaction as;
Fe₂O₃ + 3CO → 2Fe + 3CO₂
- Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
- Mass of CO as 84 grams
We are required to calculate the mass of CO₂ that will produced.
<h3>Step 1: Calculate the number of moles of CO</h3>
Moles = Mass ÷ Molar mass
Molar mass of CO = 28.01 g/mol
Therefore;
Moles of CO = 84 g ÷ 28.01 g/mol
= 2.9989 moles
= 3.0 moles
<h3>Step 2: Calculate the number of moles of CO₂</h3>
- From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
- Therefore; the mole ratio of CO to CO₂ is 1 : 1
- Hence; Moles of CO = Moles of CO₂
Moles of CO₂ = 3.0 Moles
But; mass = Moles × molar mass
Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol
= 132.03 g
Hence, the mass of CO₂ produced from the reaction is 132.03 g
Answer:
Smallest to biggest order is as follows.
C < O < Amino < Water < Glucose < Starch < protein.
Explanation:
The given atoms or molecules and their atomic masses is as follows.
Glucose - - 180 g/mol
Starch - - 692.7 g/mol
Protein - - it is vary for different proteins.
Carbon - C - 12 g/mol
Water - - 18 g/mol
Amino - - 17 g/mol
Oxygen - O - 16 g/mol
Increase the molar mass increases size of the molecules.
Therefore, Smallest to biggest order is as follows.
C < O < Amino < Water < Glucose < Starch < protein.
A vascular system<span> in </span>plants<span> is a series of tubes that </span>can<span> transport water and nutrients over a ... </span>Without<span>a </span>vascular system<span>, mosses, and liverworts cannot </span>grow<span> very large. ... These are considered to be the simplest of all </span>plants<span> and often </span>grow<span> flat along the </span>ground<span> in large leaf-like structures.</span>