Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
Answer:
75%
Step-by-step explanation:
First find the number of boys.
80 - 20 = 60
Now find the percentage my taking the number of boys upon the total, times that by 100 which gives the percentage.
× 100 = 75%
Hi, did you forget to attach the two-way table to the question? I can't seem to see it, so I can't answer your question
The answer would be =4 over 9 =4/9 hope this helps