Angular momentum is conserved, just before the clay hits and just after;
<span>mv(L/2) = Iw </span>
<span>I is the combined moment of inertia of the rod, (1/12)ML^2 , and the clay at the tip, m(L/2)^2 ; </span>
<span>I = [(1/12)ML^2 + m(L/2)^2] </span>
<span>Immediately after the collision the kinetic energy of rod + clay swings the rod up so the clay rises to a height "h" above its lowest point, giving it potential energy, mgh. From energy conservation in this phase of the problem; </span>
<span>(1/2)Iw^2 = mgh </span>
<span>Use the "w" found in the conservation of momentum above; and solve for "h" </span>
<span>h = mv^2L^2/8gI </span>
<span>Next, get the angle by noting it is related to "h" as; </span>
<span>h = (L/2) - (L/2)Cos() </span>
<span>So finally </span>
<span>Cos() = 1- 2h/L = 1 - mv^2L/4gI </span>
<span>m=mass of clay </span>
<span>M=mass of rod </span>
<span>L=length of rod </span>
<span>v=velocity of clay</span>
<span>It is possible to determine which cart to which ch is connected if the graph would show electrical charge, ie, amps or voltage. If the graph showed a series circuit diagram this would also allow determination. Bottom line is that a correct graph data will show the requested information.</span>
No baby you baby no se que no se le da la gana de que se vaya de vacaciones yes because
Frequency= speed/ wavelength
=0.5m/s divided 0.1.m
=5.0 Hz
The answer would be letter D.
I'm not quite sure what happens to Fay so I didn't finish but hope it helps