Slope intercept form is y=mx+b where m is the slope and b is the y part of an intercept where x is 0. So the equation for slope (y1-y2)/(x1-x2) with y1 and y2 the y values of 2 points and x1 and x2 those points' x values, so if you would use the points (-2,0) and (0,5) (I used intercepts because they are easier, but you can use any points on the line) you would get (0-5)/(-2-0) and then 5/2 for the slope. plugging in then you get y=5/2*x+5
3-(2x-5)<-4(x+2)
8-2x<-8-4x
16<-2x
-8 > x. or equivalently x<-8