Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16, we get 32+41-16+16=73
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12
Each side (including PQ) then equals 5x+16=5*12+16=76
The initial amount of the money is £11,000 and the interest is 3.9% per year for first 3 years and then 4.5% after that. If Dan invests it for 7 years, that means the interest would be 3 years of 3.9% and 4 years of 4.5%.
The calculation would be:
total money= initial amount * interestrate1 * interest 2
total money= £11000 *(100%+3.9%)^3<span>*(100%+4.5%)^4
</span>total money= £11000 *(103.9%)^3 * (104.5%)^4
total money= £11000 * <span>1.121622319 </span>* 1.1925186
total money= £14,713.11
Answer:
7a 3 −7a+1
Step-by-step explanation: I hope this help.
STEP
1
:
Equation at the end of step 1
((7a3 - 2a) - 2) + (3 - 5a)
STEP
2
:
Polynomial Roots Calculator :
2.1 Find roots (zeroes) of : F(a) = 7a3-7a+1
Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F(a)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 7 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1,7
of the Trailing Constant : 1
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 1.00
-1 7 -0.14 1.98
1 1 1.00 1.00
1 7 0.14 0.02
Polynomial Roots Calculator found no rational roots
Final result :
7a3 - 7a + 1
Answer:
The smallest positive integer solution to the given system of congruences is 30.
Step-by-step explanation:
The given system of congruences is
where, m and n are positive integers.
It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as
Now, we can say that m>n because m and n are positive integers.
For n=1,
19 is not divisible by 5 so m is not an integer for n=1.
For n=2,
The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is
Therefore the smallest positive integer solution to the given system of congruences is 30.
