Before the impact, let the velocity of the baseball was v m/s.
After being hit by the bat its velocity is -2v
So, change in velocity, Deltav=v-(-2v)=3v
Acceleration is defined as the rate of change in velocity, i.e. actual change in velocity divided by the time taken to change it. Time taken to change velocity is the time of actual contact of the bat and ball, i.e. 0.31 s.
a=(Deltav)/(Deltat)
=(3v)/0.37
Therefore, a/v=3/0.31=9.7 s^-1
So, the ratio of acceleration of the baseball to its original velocity is 9.7.
Answer:
104 N
Explanation:
m = 1300 kg
a = 0.08m/s^2
F = 1300*0.08
F = 104 N
Newtons is the unit of force.
Answer: 3.41 s
Explanation:
Assuming the question is to find the time the ball is in air, we can use the following equation:
Where:
is the final height of the ball
is the initial height of the ball
is the initial velocity of the ball
is the time the ball is in air
is the acceleration due to gravity
Then:
Multiplying both sides of the equation by -1 and rearranging:
At this point we have a quadratic equation of the form , which can be solved with the following formula:
Where:
Substituting the known values:
Solving the equation and choosing the positive result we have:
This is the time the ball is in air
Answer:
C hope it helps
call the client and inform her that she was incorrectly charged.
Answer:
5 Days to Seconds = 432000
Explanation: