A team of 5people to be selected from 7women & 6men. Find the number of different teams that could be selected if there must
be more women than men in the team
1 answer:
Answer:
1246 teams
Step-by-step explanation:
We are told there are 7women & 6men.
If 5 people are selected and there must be more women than men in the team.
This means there must be a minimum of 3 women.
Thus;
For 3 women;
7C3 × 6C2 = 525
For 4 women;
7C4 × 6C3 = 700
For 5 women;
7C5 × 6C0 = 21
Thus;
Total = 525 + 700 + 21 = 1246 teams
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Answer:
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I hoped this helped have a good day :)
AB=6 but DE=2(AB) so DE=2(6)=12
I’m guessing
The second and third ones are the true ones