The area of a circular sector of central angle α (in radians) in a circle of radius r is given by
... A = (1/2)r²×(α - sin(α))
Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.
... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))
... A ≈ 16.07
Radii are in inches so the units of area will be in². The appropriate choice is
... 16.10 in²
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It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.
Change the ratios to decimals and compare:
7 / 12 = 0.583
7 / 8 = 0.875
So 7:12 is less than 7/8
The answer is <
The answer is Hundredths place
Answer:
Wheres the function, what do u mean by captionless image
The part of the quadratic formula that dictates whether the function is factorable or not is B. b^2 - 4ac. This determines the number of real, imaginary, negative and positive roots.
In the equation <span>2x^2 + 7x + 3,
we use the quadratic formula
x = -b +- sqrt (b2 -4ac) /2a = -7 +- </span><span>sqrt (49 -24) /4
the answers are x1 =-0.5 and x2 = -3.</span>
