9x - 2y = 11 ... (i)
5x - 2y = 15 ... (ii)
Subtracting equation (ii) from (i) we get;
4x + 0 = -4
4x=-4 , x = -1
Replacing x = -1 in equation (i) we get;
9(-1) - 2y = 11
-9 - 2y = 11
-2y = 20
y = 20 ÷ -2 = -10
The solution to the system of equations is (-1,-10).
Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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Answer:
(20.60-5)/0.10=156 Papers
Step-by-step explanation:
It was 11 hours because if the temperature drops 2 degrees after every hour, after 11 hours, the temperature would have dropped 22 degrees and 62 - 22 = 40.
Answer:
We suppose that a is the old price in cents
the total cost of 9.20 $ equals 920 cents
so we have 20 liters bought with the old price (a) and 10 liters with the new price (a + 2). This is translated into this equation where a is the old price therefore our quest to be answered
20 xa + 10 x (a + 2) = 920 (cents)
20 xa + 10 xa + 20 = 920
30 xa + 20 = 920
30 xa = 920 - 20
30 xa = 900
a = 900: 30
a = 30 (cents)
therefore the old price for 1 liter of petrol is 30 cents
(hope this helps can i plz have brainlist :D hehe)
Step-by-step explanation: