Answer:
The perimeter of a rhombus with diagonals of 12 feet and 18 feet would be 60 feet.
Step-by-step explanation:
Perimeter of a rhombus: S1 + S2 + S3 + S4 = answer. (S stands for side.)
12 ft. + 18 ft. + 12 ft. + 18 ft. = 60 ft.
• Imagine we are using these two points to draw a triangle where new point E is a right angle with coordinates (-1, -9)
• FE = 5
• EC = 4
• FE^2 + EC^2 = FC^2
• (25) + (16) = 41 = FC^2
• FC = square root(41)
Answer:
something with a volume of 64 ft³, such as a box 4 ft × 4 ft × 4 ft
Step-by-step explanation:
The volume of the smaller box is (1 ft)³ = 1 ft³. So 64 of them require a box with a volume of 64 ft³.
The most compact of such boxes is one that is cube-shaped itself. Such a box would have dimensions of ...
∛(64 ft³) = 4 ft
A box that is 4 ft × 4 ft × 4 ft would hold the 64 smaller boxes.
Using synthetic division, we find the result of the division
(6x^4 +2x^3 -6x^2 -14x -1)/(3(x +1/3))
to be ...
(6x^3 -6x -12)/3 +3/(3x +1)
The result is ...
2x^3 -2x -4 +3/(3x+1)