Step-by-step explanation:
- sinx+sin(x+4x) =cot2x
- sinx+sinx cos4x+cosx sin4x=cot2x
sinx+sinx cos4x=sinx (1+cos4x) =
sinx (1-1+2(cos2x)^2) =2sinx (cos2x)^2
sin4x=2sin2xcos2x
2sinx(cos2x)^2+cosx+2sin2xcos2x=cot2x
2sinxcos2x(cos2x+2(cosx)^2)=cot2x
but 2(cosx)^2=cos2x+1
2sinxcos2x(cos2x+cos2x+1)=cos2x/sin2x
(2sinxsin2x)(2cos2x+1) =1
(4cosx(sinx)^2)(2cos2x+1) =1
Answer is 3x -24
Step by step
We perform distributive multiplication of the number outside the parentheses by the numbers inside the parentheses
The answer is c or the third option. If we start at one we get (4(1)-9)=-5, then we can do 2 and we get (4(2)-9)=-1. Lets do 3 (4(3)-9)=3. Now 4 (4(4)-9)=7. Now 5 and our last one (4(5)-9)=11. Now notice we get -5+-1+3+7+11.
Answer:
The correct option is;
The ratio of the area of the scale drawing to the area of the sign is equal to the square of the scale factor
Step-by-step explanation:
Here we have a scale factor of 1:8
Therefore area of drawing = 1/2×base, b×height, h = 1/2×b×h
Hence, the area of the triangular sin will be given by 1/2×8×b×8×h
Area of triangular sign = 64 × 1/2×b×h
Hence the ratio of the area of the scale drawing to the area of the triangular sign is equal to the square of the scale factor.
The anwser to your question is 1 and 5/7
