(x+a)^4 = ^4C_0 x^4 + ^4C_1 x^{4-1} a + ^4C_2x^{4-2}a^2 + ^4C_3x^{4-3}a^3 + ^4C_4x^{4-4}a^4
= x^4 + 4x^3a + 6x^2a^2 + 4xa^3 + a^4
Answer:
1. A
2. B
3. D
Step-by-step explanation:
Use PEMDAS to solve all
1.
8^2 - 6*2
8*8 - 6*2
64 - 12 = 52
2.
4^2 * 3 + 4 * 2
4 * 4 * 3 + 4 * 2
16 * 3 + 8
48 + 8 = 56
3.
9^2 - 2(5+3)
9 * 9 - 2(8)
81 - 16 =65
Answer:
Table B
Step-by-step explanation: skidaddle skidoodle you probably know the rest 8)
U see I would help but just because u said “pwease” I’m not :)
I believe the answer is 75 I am not sure but I adds up because 4*.75 equals to 3 there is another way to solve this though we can do the is over of equals % over 100 then we still get three have a nice day and good luck on your assignment (:
