First, we always have to list them from least to greatest: 3,7,10,11,12,14,15,17,17,21.
A. I attached an image of the cumulative frequency table.
B. I wasn't able to make a histogram since I can't find any templates or programs to create it on.
Part C:
Mean: 12.7
Median: 26/2=13
Mode: 17
Range: 21 -3 = 18
Part D:
Minimum: 3
First Quartile: 10
Third Quartile: 17
Maximum: 21
E. I can't a program again, but I can help you over a call if you'd wish.
Part F:
40th Percentile: 0.31
Answer:
Sarah bought 2 coach tickets and 3 first class tickets.
Step-by-step explanation:
Let c and f represent the numbers of coach and first class tickets purchased. Then c + f = 5, so that c = 5 - f.
The pricing equation is therefore
$380c + $1080f = $4000. Subbing 5 - f for c, we get the revised equation
380(5 - f) + 1080f = 4000.
After simplification, this becomes:
-380f + 1080f = 2100, or
700f = 2100.
Then f = 3 and c = 5 - f = 5 - 3 = 2.
Sarah bought 2 coach tickets and 3 first class tickets.
Answer:
-21
Step-by-step explanation:
The total number of fish bought was 320. And you know she bought two types of fish. The best way to solve this is guess and check. It would be the fastest. So she bought 7 times as many trigger-fish as parrot fish that means the number of trigger-fish bought was 7p. This means 320 = 7p +p. So all you do is take educated guesses for the number of parrot fish and check if it is right. So if she bought 50 parrot fish. 7(50) + 50 = 400. Close but a bit high. Lets keep guessing. 7(35) + 35 = 245. So now we know the answer is between 50 and 35. So lets try 40. 7(40) + 40 =320. That works so we know she bought 40 parrot fish and 280 trigger-fish.
