The value of a is between 0 and 1.
It looks like the differential equation is
Check for exactness:
As is, the DE is not exact, so let's try to find an integrating factor <em>µ(x, y)</em> such that
*is* exact. If this modified DE is exact, then
We have
Notice that if we let <em>µ(x, y)</em> = <em>µ(x)</em> be independent of <em>y</em>, then <em>∂µ/∂y</em> = 0 and we can solve for <em>µ</em> :
The modified DE,
is now exact:
So we look for a solution of the form <em>F(x, y)</em> = <em>C</em>. This solution is such that
Integrate both sides of the first condition with respect to <em>x</em> :
Differentiate both sides of this with respect to <em>y</em> :
Then the general solution to the DE is
Answer:
1241
Step-by-step explanation:
∴
L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260
∴
the required number is 1260 - 19 = 1241
Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.
Answer:
The expectation of the policy until the person reaches 61 is of -$4.
Step-by-step explanation:
We have these following probabilities:
0.954 probability of a loss of $50.
1 - 0.954 = 0.046 probability of "earning" 1000 - 50 = $950.
Find the expectation of the policy until the person reaches 61.
Each outcome multiplied by it's probability, so:
The expectation of the policy until the person reaches 61 is of -$4.