Complete Question
A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.
What is the refrigerator's coefficient of performance? COP
(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP
Answer:
a
b
Explanation:
From the question we are told that
The lower operation temperature of refrigerator is
The upper operation temperature of the refrigerator is
Generally the refrigerators coefficient of performance is mathematically represented as
=>
=>
Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as
=>
=>
Answer:
F = 0.78[N]
Explanation:
The given values correspond to forces, we must remember or take into account that the forces are vector quantities, that is, they have magnitude and direction. Since we have two X-Y coordinate axes (two-dimensional), we are going to decompose each of the forces into the X & y components.
<u>For F₁</u>
<u /><u />
<u>For F₂</u>
<u>For F₃</u>
<u /><u />
Now we can sum each one of the forces in the given axes:
Now using the Pythagorean theorem we can find the total force.
Answer:
thank for making me give up on life
Explanation:
I thought the stuff I had was hard wth is even that
In a circuit having 2 lamps are connected in parallel to a battery
then the two lamps will be having the same potential as the battery
i.e
As per Ohm's law,
and
In other words, each lamp's current is inversely related to its individual resistance. We only know the current in one of the bulbs in this specific instance. We would therefore need further information in order to calculate the current in the other light. Therefore, there isn't enough data to make a statement.
Under the assumption that all physical parameters, including temperature, remain constant, Ohm's law asserts that "the voltage across a conductor is directly proportional to the current flowing through it".
Learn more about Ohm's law here
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