Answer:
128 g of Li will react with 86.1 g of N₂ to completely consume it.
Solution:
The balance chemical equation is as follow,
<span> 6 Li + N</span>₂ → 2 Li₃<span>N
According to this equation,
28 g (1 mole) N</span>₂ reacts with = 41.64 g (6 moles) of Li
So,
86.1 g of N₂ will react with = X g of Li
Solving for X,
X = (86.1 g × 41.64 g) ÷ 28 g
X = 128 g of Li
The four states of matter are solid, liquid, gas, and plasma.
Solid: a solid object has a definite volume and shape i.e. A box
Liquid: liquid has a definite volume but no definite shape i.e. Water
Plasma: plasma has some of the properties of gas but it's a good trainer of electricity and is a affected in a magnetic field i.e. A star
Gas: gas does not have a definite shape or volume so it takes the shoe of its container i.e. Balloon
The initial temperature is 137.34 °C.
<u>Explanation:</u>
As the specific heat formula says that the heat energy required is directly proportional to the mass and change in temperature of the system.
Q = mcΔT
So, here the mass m is given as 23 kg, the specific heat of steel is given as c = 490 J/kg°C and the initial temperature is required to find with the final temperature being 140 °C. Also the heat energy required is 30,000 J.
ΔT =
ΔT =
Since the difference in temperature is 2.66, then the initial temperature will be
Final temperature - Initial temperature = Change in temperature
140-Initial temperature = 2.66
Initial temperature = 140-2.66 = 137.34 °C
Thus, the initial temperature is 137.34 °C.
The reactant being used up is called limiting reagent as it limits the total amount of product produced.
if 4 units of HCL gives 2 units of Cl therefore
4:2
0.98:x
x=(0.98*2) /4
x=0.49L
<span>To find the mass of 3.00 moles of magnesium chloride (MgCl2), first record the atomic mass of magnesium (Mg) and chloride (Cl), which are both listed on the periodic table as follows:
Mg=24 g/mole
Cl=38 g/mole
Now, double the Cl mass since there are 2 Cl moles in MgCl2 and then add it to the Mg mass like so:
(38 g/mole*2 moles)+24 g/mole=100 g/mole
Finally, to calculate the mass of 3.00 moles of MgCl2, convert the combined atomic mass to grams as follows:
3.00 moles * 100 g/mole = 300 g</span>
