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2 years ago

18. Given PQ | BR. Then find the measure of x

Mathematics

1 answer:

maria [59]2 years ago

7 0

Answer:

∠x = 70°

Step-by-step explanation:

Given that PQ||BR

Line PQ and BR with transversal AC,

∠x + ∠ACR = 180° {Co-interior angles}

⇒∠x + 110° = 180° {From what I can see it looks like 110.}

⇒∠x = 180° - 110°

⇒∠x = 70°

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33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

2 years ago

Five-sixths of the thirty students passed their test. How many student did not pass

vlada-n [284]

Answer:

5 as 5/6 of 30= 25 and 25+5 =30

Step-by-step explanation:

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2 years ago

What is The Value of X

Alekssandra [29.7K]

$\bold{ANSWER:}$
x = 11

$\bold{SOLUTION:}$

4 0

1 year ago

Al sumar y/o restar números decimales, siempre se debe aplicar la norma de los signos. * 1 punto FALSO VERDADERO

Luden [163]

Answer:

La norma de los signos es para el producto de números reales, y la norma es la siguiente.

(+)*(+) = (+)

(+)*(-) = (-)

(-)*(+) = (-)

(-)*(-) = (+)

Es decir, el producto de dos números de mismo signo es siempre positivo

El producto de dos números de distinto signo es siempre negativo.

Particularmente, para la suma esta norma no funciona (pues no está definida para la suma)

Pero en casos como:

5 - (-4)

(esto sería: "la diferencia entre cinco y menos cuatro")

notar que podemos reescribir esto como:

5 + (-1)*(-4)

Ahora podemos aplicar la norma de los signos:

5 + 4 = 9

Donde aplicamos la norma de los signos,

Podemos concluir que, si bien es una regla que aplica al producto, siempre la tenemos que tener en cuenta en cualquier operación que hagamos.

Por lo podemos concluir que la respuesta correcta es verdadero.

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2 years ago

John needs to make a scale drawing of his school building for art class. If the building is 256.25 meters long, and John scales

olchik [2.2K]

The answer will be 10.25 inches
$256.25 \div 25 = 10.25$

good luck

8 0

2 years ago

18. Given PQ | BR. Then find the measure of x​

18. Given PQ | BR. Then find the measure of x