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2 years ago

A triangle has two angle measures of 20 degrees and 30 degrees. Find the third angle. This triangle is a(n) ________ triangle

Mathematics

2 answers:

Artist 52 [7]2 years ago

7 0

Answer:130 degrees. it is scalene triangle

Step-by-step explanation:

all angles in a triangle add up to 180.

20+30=50

180-50=130

a scalene triangle has all sides different

Zielflug [23.3K]2 years ago

4 0

Answer:

an obtuse triangle cause the other angle is more than 90

Step-by-step explanation:

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ASAP Which power can you write to represent the volume of the cube shown? Enter the power as an expression with a base and an ex

n200080 [17]

Answer:

The power for the volume of the cube is '3'.

Exponent form of the volume is

Volume of the cube is inch³.

Step-by-step explanation:

We are given,

A cube with side equal to inches.

As we know,

Volume of a cube =

Thus, we get,

Volume of the given cube is,

Volume =

i.e. Volume = inch³

Thus, we have,

The power for the volume of the cube is '3'.

Exponent form of the volume is

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2 years ago

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REY [17]

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2 years ago

Solve the following equations;- x - 9 /√x + 3 =1

fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

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$\sf\implies x - 9 =\sqrt{ x +3}$

Squaring both sides ,

$\sf\implies (x - 9)^2 = x + 3$

Simplify the whole square ,

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Add 3 and subtract x on both sides ,

$\sf\implies x^2 -18x-x +81-3=0$

Simplify ,

$\sf\implies x^2 -19x +78=0$

Split the middle term of the quadratic equation,

$\sf\implies x^2-13x-6x+78=0$

Take out common ,

$\sf\implies x( x -13)-6(x-13)=0$

Take out ( x -13 ) as common ,

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Equate both factors to 0 ,

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Hence the value of x is 13 or 6 .

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2 years ago

What is the method of comparing Coefficient

Svetllana [295]

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2 years ago

Simplify completely. 10 points (:

zubka84 [21]

Answer:

2y^4√5

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

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3 years ago

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