The cost of boiling 500 cm³ of water using the 3 KW Kettle is 1.35p
<h3>What is power? </h3>
This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:
Power (P) = Energy (E) / time (t)
P = E / t
<h3>How to determine the energy</h3>
- Power (P) = 3 KW
- Time (t) = 3 mins = 3 / 60 = 0.05 h
- Energy (E) =?
E = Pt
E = 3 × 0.05
E = 0.15 KWh
<h3>How to determine the cost</h3>
- Energy (E) = 0.15 KWh
- Cost per unit = 9p
- Cost =?
Cost = Energy × cost per unit
Cost = 0.15 × 9
Cost = 1.35p
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The correct answer is C. Lost time is never found again
Explanation:
One of the most relevant personality theories is Type A and Type B personality theory that proposes two main types of personalities by grouping different personality traits. In the case of Type A personality, this refers to individuals that are very organized, impatient, and concerned with time and goals. On the opposite, Type B personality includes individuals that are more relaxed in different aspects.
According to this, one maxim that applies to Type A personality is "Lost time is never found again" because people with this personality are concerned about time and therefore, loss of time is considered highly negative by them. Also, due to their ambitions and concern with goals they want to avoid losing time as this is equivalent to work, money, goals, etc.
Answer:
Emechanical=mgh+mν²
Explanation:
The equation for the total mechanical energy is:
Emechanical=Epotential+Ekinetic
In which,
Epotential=mgh; m: mass of the body, g: gravity; h: height
Ekinetic=mν²; m: mass of the body, ν: velocity of the body
So,
Emechanical=mgh+mν²
To solve this problem we will apply the principle of buoyancy of Archimedes and the relationship given between density, mass and volume.
By balancing forces, the force of the weight must be counteracted by the buoyancy force, therefore
Here,
m = mass
g =Gravitational energy
The buoyancy force corresponds to that exerted by water, while the mass given there is that of the object, therefore
Remember the expression for which you can determine the relationship between mass, volume and density, in which
In this case the density would be that of the object, replacing
Since the displaced volume of water is 0.429 we will have to
The density of water under normal conditions is , so
The density of the object is