Answer:
P = $6000
i = 3.5% = 0.035
n =20
Future value = P*(1+i/m)^nm
If compounded annually = 6,000*(1+0.035) ^20 = 6,000*(1.035)^20 = 6,000*1.9898 = $11938.80
If compounded semi-annually = 6,000*(1+0.035/2)^20*2 = 6,000*(1+0.0175)^40 = 6,000*(1.0175)^40 = 6,000*2.00159734319 = $12009.58405914 = $12009.58
If compounded quarterly = 6,000*(1+0.035/4)^20*4 = 6,000*(1+0.00875)^80 = 6,000*(1.00875)^80 = 6,000* 2.00763065501 = $12045.78393006 = $12045.78
If compounded monthly = 6,000*(1+0.035/12)^20*12 = 6,000*(1+0.0029167)^240 = 6,000*(1.0029167)^240 = 6,000 * 2.01171808178 = $12070.30849068 = $12070.31
If compounded weekly = 6,000*(1+0.035/52)^20*52 = 6,000*(1.00067307692)^1040 = 6,000 * 2.01327857595 = $12079.6714557 = $12079.67
If compounded daily = 6,000*(1+0.035/365)^20*365 = 6,000*(1.00009589041)^7300 = 6,000*2.01368511398 = $12082.11068388 = $12082.11