Answer:
hydrogen atom when it drops from N 5 to N 2?
so, 275 kJ of energy is released when one mole of electrons "falls" from n = 5 to n = 2. E = hc/λ (this energy corresponds to the energy of one photon; the energy calculated in this problem is for one mole of photons so we will change this after we change the units from kJ to J)
Explanation:
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This is true do to all the other particules around
Answer : The concentration of is,
Explanation :
When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is and is excess reagent.
First we have to calculate the moles of KSCN.
Moles of KSCN = Moles of = Moles of =
Now we have to calculate the concentration of
Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L
Thus, the concentration of is,
Answer: 1 proton, 0 electron and 1 neutron are present in 1 H⁺ isotope.