Answer:
See Explanation
Explanation:
From Gay-Lussac's law of combining volumes;
Equation of the reaction; 2H2(g) + O2(g) -------> 2H2O(g)
Ratio of volumes; 2 : 1 : 2
Initial volumes; 500cm^3 500cm^3 0 cm^3
Reacting volumes; 500cm^3 250cm^3 500cm^3
Final Volumes; 0 cm^3 250 cm^3 500 cm^3
We can easily see from the table that the limiting reactant is oxygen.
Hence, the mass of water formed is obtained from;
1 mole of gaseous water occupies 22400 cm^3
x moles of water occupies 500cm^3
x = 500cm^3 * 1 mole/22400 cm^3
x = 0.022 moles of water
Mass of water = 0.022 moles of water * 18 g/mol
Mass of water = 0.396 g
