In similar figures, the ratio between corresponding sides are the same.
Simplify the two to see that they are equal.
The top and bottom of the left fraction are divisible by 5.
The top and bottom of the right fraction are divisible by 7.
Of course, the dimensions of that third picture would have to be this fraction.
Let's test these answers.
⇒ A is not a solution
⇒
B is the solution
(divide the top and bottom by 6)
Answer:
24ft²
Step-by-step explanation:
divide up the shape:
big triangle:
(looking for base)
9.8²= 4² + b²
b = 8.95ft
(finding area)
0.5*8.95*4 = 17.9ft²
small triangle:
(looking for base)
12-8.95=3.05ft
(finding area)
0.5*3.05*4 = 6.1ft²
Whole Shape:
17.9+6.1 = 24ft²
Answer:
The distance A’C’ is 4.47 units
Step-by-step explanation:
Before we go on, we need to get the appropriate transformation
Mathematically, we have a 90 degrees clockwise rotation yielding the following;
(x,y) to (-y,x)
A is (-4,1)
C is (-2,5)
By transforming, we have
A’( -1,-4)
C’ (-5,-2)
To get the magnitude of the line segment, we are going to use the distance formula between points
We have this as;
D = √(x2-x1)^2 + (y2-y1)^2
D = √(-5-(-1))^2 + (-2-(-4))^2
D = √(-4)^2 + (2)^2
D = √(16 + 4)
D = √20
D = 4.47 units
Answer:
The only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities.
Step-by-step explanation:
See the graph attached to this question.
The solution of the set of inequalities is given by the shaded region on the graph.
Now, the point (0,5) is outside this shaded region, hence it can not be the solution.
The point (3,0) also is outside this shaded region, hence it can not be the solution.
The point (-3,0) also is outside this shaded region, hence it can not be the solution.
Now, the only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities. (Answer)
one mole of water contains 6.02 x 1023 MOLECULES of water. But each molecule of water contains 2 H and 1 O atom = 3 atoms, so there are approximately 1.8 x 1024 atoms in a mole of water.
