Answer:
- The room mantained at a lower temperature will contain more air molecules.
Explanation:
1) Since the two rooms are <em>connected by an open door</em>, you assume pressure equilibrium: the pressure on the two rooms is the same.
2) Since you consider <em>two equal size rooms</em>, both volumes are equal.
3) Assuming ideal gas behavior, pressure (P), temperature (T), volume (V) and number of moles (n) are related by the equation PV = nRT
4) Naming T₁ the lower temperature, T₂ the higher temperature, n₁ the number of moles of air in the room at lower temperature, and n₂ the number of moles of air in the room at higher temperature, you get:
- n₁ T₁ = n₂ T₂, or n₁ / n₂ = T₂ / T₁
5) That means that the amount of molecules (number of moles) is inversely related to the temperature: the higher the temperature the lower the number of moles, and the lower the temperature the greater the number of moles.
Hence, the answer is that <em>the room that contains more air molecules is the room mantained at a lower temperature.</em>
Answer : The pH of the solution is, 4.9
Explanation : Given,
Dissociation constant for acetic acid =
Concentration of acetic acid = 0.05 M
Concentration of sodium acetate = 0.075 M
First we have to calculate the value of .
The expression used for the calculation of is,
Now put the value of in this expression, we get:
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
Therefore, the pH of the solution is 4.9.
Answer:
Paper
Explanation:
In chromatographic separation, two different phases are important; a stationary phase and a mobile phase.
The stationary phase is the phase that does not move. Substances are separated based on how fast or slowly they move in the stationary phase.
The mobile phase is usually the solvent(or mixture of solvents) that carries the solutes through the stationary phase.
The stationary phase is usually composed of a porous material. Paper is a porous material. The mobile phase is trapped between the cellulose fibers of the paper and separation is achieved.
A I think that a bar graph would best represent this information.