Answer:
All numbers can be written as a product of the prime numbers that conform them.
A) Find two numbers with a common factor of 3 only.
for example:
2*3 = 6
7*3 = 21
Both numbers have the factor 3 in them, and because the other two numbers are primes, we can be sure that the 3 is the only common factor.
B) Write a pair of numbers with a common factor of 2, 3 and 6.
Here we can write:
2*3*2 = 12
3*2*5 = 30
Those two numbers have the common factors 6, 2 and 3.
C) Write a pair of numbers with common factors of 3, 6 and 9.
3*2*3 = 18 (has the factors 2, 3, 3*2 = 6, 3*3 = 9)
-3*2*6 = -36
Both have the common factors 3, 6 and 9 (and they share more common factors like 2, this happens because 6 = 3*2, so if 6 is a common factor, 2 also must be)
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
<u />
<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A
Explanation
Step 1
the density of an object is given by:
Step 2
let
Step 3
replace,
I hope this helps you
247.62 x 0.15 = 37.143
round to $37.14
I hope that helped :)
f (x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.
Do you see the h and k in your equation?
-h = -(-2) = 2
We see that k = -4.
Our vertex is (2, -4).