If you draw only 25 balls, you could draw the 25 odd-numbered balls. However, there will then be no odd-numbered balls left, so when you draw two more you will be guaranteed to get two even-numbered balls. Thus, the minimum is 25+2=27 balls.
Answer:
1/6 for the cube and 1/2 for the coin
it would be 4/6 or 2/3 both are the same
Step-by-step explanation: sorry if im wrong btw
so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).
so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?
Multiply 9 and 5 then multiply by .5 giving you 22.5 so I’d say that’s your best option