Answer:
bederr
Step-by-step explanation:
baderdkd0ensdeussdk fmdikjxijod djieos-sxmsososjs0hsoisnsohsowb9sbnszolsis
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i got 5 points mfor free haha!!
14 degrees. It equals half the intercepted arc.
(See attached graphic)
Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
Find out more on combined area at brainly.com/question/12966430
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Answer:
length of segment AB is 13
OR
AB = 13
Step-by-step explanation:
Use the Pythagorean Theorem with c being the length of segment AB.
a^2 + b^2 = c^2
5^2 + 12^2 = c^2
169 = c ^2 (square root both sides to get c by itself)
13 = c
150 = 2 * 3 * 5 * 5. So the code for the door is 2355 in some order.
