For the second question (5/6)/(4) is the same as (5/6)*(1/4) so just multiply across and you get (5/24)
Answer:
-1,0, 6.3,
Step-by-step explanation:
if its right mark me brilliant please
Answer:
840
Step-by-step explanation:
Last year, 800 students attended the career fair at West High School.
And, this year the number of students who attended the career fair increased by 5%.
We are asked how many students attended the career fair at West High School this year.
Therefore, the number of students attended the career fair at West High School will be ![800[1+\frac{5}{100} ] =800 \times 1.05 = 840](https://tex.z-dn.net/?f=800%5B1%2B%5Cfrac%7B5%7D%7B100%7D%20%5D%20%20%3D800%20%5Ctimes%201.05%20%3D%20840)
. (Answer)
Depends what Ferrari car it is.
Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
