Find the midpoint of the line segment with end coordinates of (2,1) and (4,5)

GuDViN [60]

Answer:

Cluster Sampling

Step-by-step explanation:

I cant be 100% sure as i am not in statistics, but by definition cluster sampling is a probability sampling technique where researchers divide the population into multiple groups (clusters) for research (in this case its the phone book). Researchers then select random groups (three random pages) with a simple random or systematic random sampling technique for data collection and data analysis(interviews).

so that appears to be what is happening in this scenario.

6 0

2 years ago

A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer

OLEGan [10]

Answer:

The probability is $P( p < 0.9207) = 0.0012556$

Step-by-step explanation:

From the question we are told

The population proportion is $p = 0.96$

The sample size is $n = 227$

The number of graduate who had job is k = 209

Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

$\mu_x = p = 0.96$

Generally the standard deviation of this sampling distribution is

$\sigma = \sqrt{\frac{p (1 - p )}{n} }$

=> $\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }$

=> $\sigma = 0.0130$

Generally the sample proportion is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{209}{227}$

=> $\^ p = 0.9207$

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

$P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )$

$\frac{\^ p - p}{\sigma } = Z (The \ standardized \ value\ of \ \^ p )$

$P( p < 0.9207) = P(Z< -3.022 )$

From the z table the area under the normal curve to the left corresponding to -3.022 is

$P(Z< -3.022 ) = 0.0012556$

=> $P( p < 0.9207) = 0.0012556$

6 0

2 years ago

The Lewis family and the Perry family each used their sprinklers last summer. The water output rate for the Lewis family's sprin

Rashid [163]

The Lewis family and the Perry family each used their sprinklers last summer. The water output rate for the Lewis family's sprinkler was 15 L per hour. The water output rate for the Perry family's sprinkler was 40 L per hour. The families used their sprinklers for a combined total of 65 hours, resulting in a total water output of 1850 L . How long was each sprinkler used

Answer:

Hours of use of sprinkler by Lewis family is 30 hours.

Hours of use of sprinkler by Perry family is 35 hours.

Step-by-step explanation:

Let W = hours of use by Lewis family

65 - W = hours of use by Perry family

Then;

15W + 40*(65 - W) = 1850

15W + 2600 - 40W = 1850

(15 - 40)W = 1850 - 2600

-25W = −750

W = 750/25 = 30

Therefore;

W = 30

65 - W = 65 - 30 = 35

Hence,

Hours of use by Lewis family is 30 hours.

Hours of use by Perry family is 35 hours.

3 0

2 years ago

2. make sure you show all your work for full points. what is z?

LenKa [72]

Answer:

I don't understand what the means

7 0

1 year ago

Hey guys!! Kon'nichiwa!!

mina [271]

Answer:

1. 1.79

2.11.486

3.2.3562

4.61.4

5. 115.7226

( 이게 옳은 거니?)

(;ŏ﹏ŏ)

6 0

2 years ago

Read 2 more answers

Find the midpoint of the line segment with end coordinates of (2,1) and (4,5)​

Find the midpoint of the line segment with end coordinates of (2,1) and (4,5)