Answer:
Solution given:
Let there be a point P(x, y) equidistant from
A(-3, 2) and B(0,4),
so PA = PB,
squaring both side
x²+6x+9+y²-4y+4=x²+y²-8y+16
x²+6x+y²-4y-x²-y²+8y=16-4-9
6x-4y+8y=3
<u>6x-4y=3 </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>r</u><u>e</u><u>q</u><u>u</u><u>i</u><u>r</u><u>e</u><u>d</u><u> </u><u>l</u><u>o</u><u>c</u><u>u</u><u>s</u><u> </u>
<u>A</u><u>c</u><u>t</u><u>u</u><u>a</u><u>l</u><u>l</u><u>y</u><u>:</u>
<u>A</u><u> </u><u>locus</u><u> </u><u>is</u><u> </u><u> </u><u>a curve or other figure formed by all the points satisfying a particular equation of the relation between coordinates, or by a point, line, or surface moving according to mathematically defined conditions.</u>